html页面显示的问题_html/css_WEB-ITnose

function showData(row) {            var tr = document.createElement('tr');            var td1 = document.createElement('td');            td1.innerHTML = row.DEVID;            var td2 = document.createElement('td');            td2.innerHTML = row.Area;            var td3 = document.createElement('td');            td3.innerHTML = row.USERNAME;            var td4 = document.createElement('td');            if (row.IsUsable == '1')            {                td4.innerHTML = "可用";            }            else             {                td4.innerHTML = "不可用";            }             var td5 = document.createElement('td');            td7.innerHTML = row.BindDate;            tr.appendChild(td1);            tr.appendChild(td2);            tr.appendChild(td3);            tr.appendChild(td4);            tr.appendChild(td5);}我现在是写成这样的,但是页面显示 “可用不可用” 感觉不怎么好看,想用checkbox之类的的勾选来显示。那我这里应该怎么改呢?:            var td4 = document.createElement('td');            if (row.IsUsable == '1')            {                td4.innerHTML = "可用";            }            else             {                td4.innerHTML = "不可用";            }

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         function showData(row) {                  var tr = document.createElement('tr');                  var td1 = document.createElement('td');                  td1.innerHTML = row.UID;                  var td2 = document.createElement('td');                  td2.innerHTML = row.AREA;                  var td3 = document.createElement('td');                  td3.innerHTML = row.USERNAME;                  var td4 = document.createElement('td');                  if (row.ROLE == '1') {                      td4.innerHTML = "是";                  }                  else {                      td4.innerHTML = "否";                  }                  var td5 = document.createElement('checkbox');                  if (row.ISUSSELF == '1') {                      document.getElementById("checkbox").checked = true                  }                  else {                      document.getElementById("checkbox").checked = false                  }                  var td6 = document.createElement('td');                  td6.innerHTML = row.ISUSABLE;                  tr.appendChild(td1);                  tr.appendChild(td2);                  tr.appendChild(td3);                  tr.appendChild(td4);                  tr.appendChild(td5);                  tr.appendChild(td6);;                  $("#datatable > tbody").append(tr);              }

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我现在这样完全不行啊,求赐教!

首先下面的代码就不正确,根本取不到你要的元素: 

document.getElementById("checkbox").checked = true

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nbsp;html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">        无标题文档                var row = {};        row.UID = "1";        row.AREA = "China";        row.USERNAME = "Li Ming";        row.ROLE = '1';        row.ISUSSELF = '1';        $(function () {            showData(row);        });        function showData(row) {            var tr = document.createElement('tr');            var td1 = document.createElement('td');            td1.innerHTML = row.UID;            var td2 = document.createElement('td');            td2.innerHTML = row.AREA;            var td3 = document.createElement('td');            td3.innerHTML = row.USERNAME;            var td4 = document.createElement('td');            if (row.ROLE == '1') {                td4.innerHTML = "是";            }            else {                td4.innerHTML = "否";            }            var chkbox = document.createElement('input');            chkbox.setAttribute("type", "checkbox");            if (row.ISUSSELF == '1') {                chkbox.setAttribute("checked", true);            }            else {                chkbox.setAttribute("checked", false);            }            var td6 = document.createElement('td');            td6.innerHTML = row.ISUSABLE;            tr.appendChild(td1);            tr.appendChild(td2);            tr.appendChild(td3);            tr.appendChild(td4);            tr.appendChild(chkbox);            tr.appendChild(td6);;            $("#datatable > tbody").append(tr);        }        

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nbsp;html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">        无标题文档                var row = {};        row.UID = "1";        row.AREA = "China";        row.USERNAME = "Li Ming";        row.ROLE = '1';        row.ISUSSELF = '1';        $(function () {            showData(row);        });        function showData(row) {            var tr = document.createElement('tr');            var td1 = document.createElement('td');            td1.innerHTML = row.UID;            var td2 = document.createElement('td');            td2.innerHTML = row.AREA;            var td3 = document.createElement('td');            td3.innerHTML = row.USERNAME;            var td4 = document.createElement('td');            if (row.ROLE == '1') {                td4.innerHTML = "是";            }            else {                td4.innerHTML = "否";            }            var chkbox = document.createElement('input');            chkbox.setAttribute("type", "checkbox");            if (row.ISUSSELF == '1') {                chkbox.setAttribute("checked", true);            }            else {                chkbox.setAttribute("checked", false);            }            var td6 = document.createElement('td');            td6.innerHTML = row.ISUSABLE;            tr.appendChild(td1);            tr.appendChild(td2);            tr.appendChild(td3);            tr.appendChild(td4);            tr.appendChild(chkbox);            tr.appendChild(td6);;            $("#datatable > tbody").append(tr);        }        

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            var td5= document.createElement(‘input’);
            td5.setAttribute(“type”, “checkbox”);
            if (row.ISUSSELF == ‘1’) {
                td5.setAttribute(“checked”, true);
            }
            else {
                td5.setAttribute(“checked”, false);
            }

这样写表格就乱了,能把document.createElement(‘input’);加入到document.createElement(‘td’);里吗?

你都引入jquery了为什么不用jquery呢?,你是取会数据拼装table的tr,td吗?

你都引入jquery了为什么不用jquery呢?,你是取会数据拼装table的tr,td吗?

是啊,但是不是很会用

       function showData(row) {var str='';str+=''+row.UID+''+row.AREA+''+ row.USERNAME+'';str+=(row.ROLE == '1')?'是':'否';str+=''+row.ISUSABLE;+'';        $("#datatable > tbody").append($(str));      }

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nbsp;html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">无标题文档   

登录后复制登录后复制            jQuery(function($){var row = {}; row.UID = “1”; row.AREA = “China”; row.USERNAME = “Li Ming”; row.ROLE = ‘1’; row.ISUSSELF = ‘1’;//showData(row); //function showData(row) { var str=”; str+=’

‘+row.UID+’

‘+row.AREA+’

‘+ row.USERNAME+’

‘; str+=(row.ROLE == ‘1’)?’是’:’否’; str+=’

‘+row.ISUSSELF+”; $(“#datatable > tbody”).append($(str)); //}});

nbsp;html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">无标题文档   

登录后复制登录后复制            jQuery(function($){var row = {}; row.UID = “1”; row.AREA = “China”; row.USERNAME = “Li Ming”; row.ROLE = ‘1’; row.ISUSSELF = ‘1’;//showData(row); //function showData(row) { var str=”; str+=’

‘+row.UID+’

‘+row.AREA+’

‘+ row.USERNAME+’

‘; str+=(row.ROLE == ‘1’)?’是’:’否’; str+=’

‘+row.ISUSSELF+”; $(“#datatable > tbody”).append($(str)); //}});

谢谢了 ,挺好的方法,修改下就可以了

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