这篇文章主要介绍了c#实现微信红包功能,使用正态分布计算红包金额,具有一定的参考价值,感兴趣的小伙伴们可以参考一下
本文实例为大家分享了C#仿微信红包功能的具体代码,供大家参考,具体内容如下
Program.cs代码:
class Program { static void Main(string[] args) { //初始化要发起的红包基础数据 double total = 100; int num = 50; double min = 0.01; string temp; bool flag = false; Console.WriteLine(string.Format("是否需要自定义红包金额和数量(默认{0}元/{1}人)Y/N:", total, num)); temp = Console.ReadLine(); if (temp.Trim().ToLower().Equals("y") || temp.Trim().ToLower().Equals("yes")) { Console.WriteLine("请输入你要发起的红包金额:"); do { temp = Console.ReadLine(); flag = double.TryParse(temp, out total); if (!flag) { Console.WriteLine("金额必须为整数或小数,请重新输入:"); } } while (!flag); Console.WriteLine("请输入你要发起的红包个数:"); do { temp = Console.ReadLine(); flag = int.TryParse(temp, out num); if (!flag) { Console.WriteLine("红包个数必须为整数,请重新输入:"); } } while (!flag); } total -= min * num; if (total 0) { do { result = Round((double)Normal(u1.NextDouble(), u2.NextDouble(), average, variance), 2); } while (result == null || result result) { total = (double)Round((total - (double)result), 2); } else { result = total; total = 0; } } else if (i == num - 1) { total = 0; } nums[i] = Math.Round(min + (double)result, 2); //浮点运算问题,这里需要四舍五入数据才正确 Console.WriteLine(string.Format("第{0}个红包金额:{1}", i + 1, (min + result))); Console.WriteLine("剩余金额:" + ((i != num - 1 && total == 0) ? min * (num - i - 1) : total + (min * (num - i - 1)))); } Console.WriteLine("最大金额:" + nums.Max()); Console.WriteLine("最小金额:" + nums.Min()); Console.WriteLine("总额:" + Round(nums.Sum(), 2)); Console.WriteLine("初始方差:" + variance); Console.WriteLine("结果方差:" + Variance(nums)); Console.WriteLine("按任意键退出!"); Console.ReadKey(); } ////// 产生符合正态分布的随机数 /// /// 正态分布第一个随机数 /// 正态分布第二个随机数 /// 正态期望(平均值) /// 正态标准差(Math.Sqrt(方差)) /// public static double? Normal(double u1, double u2, double averageValue, double variance) { double? result = null; try { result = averageValue + Math.Sqrt(variance) * Math.Sqrt((-2) * Math.Log(u1)) * Math.Sin(2 * Math.PI * u2); } catch (Exception) { result = null; } return result; } ////// 求一组数据的方差 /// /// 要求的数组 /// public static double Variance(double[] nums) { double average = nums.Sum() / nums.Length; double sum = 0; double variance = 0; foreach (double num in nums) { sum += Math.Pow((num - average), 2); } variance = sum / nums.Length; return variance; } ////// 截取小数指定小数位,且不四舍五入 /// /// 要截取的小数 /// 截取小数后位数 /// public static double? Round(double originNum, int lastNum) { double? result = null; int index = originNum.ToString().IndexOf('.'); if (index != -1) { string temp = originNum.ToString(); result = Convert.ToDouble(temp.Substring(0, index + 1) + temp.Substring(index + 1, Math.Min(temp.Length - index - 1, lastNum))); } if (result == 0) { result = null; } else if (index == -1) { result = originNum; } return result; } }
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运行结果:
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